Jumat, 02 Mei 2014

SOAL SPK


    1.  Rangkuman Informasi kedalam Tabel

Produk
Tenaga Kerja (jam/unit)
Tanah liat (kg/unit)
Laba
Mangkok
1
3
4000
Cangkir
2
2
5000

Misalkan :
                X = Mangkok
                Y = Cangkir
                Z = Laba
  
2.    2.   Menentukan Fungsi
·         Fungsi tujuan = misalkan z= 4000x + 5000y
·         Fungsi kendala = fungsi mangkok = 1x + 3y 4000
= Fungsi cangkir = 2x + 2y 5000 

      3.  Menentukan titik potong
-          Mangkok = 1x + 3y = 4000                   
X = 0                                                              y = 0
1(0) + 3y = 4000                                         1x + 3(0) = 4000
           3y = 4000                                                          1x= 4000
             Y = 1.3                                                                x= 4000
                        (0,1)                                                                       (4000,0)
-          Cangkir = 2x + 2y = 5000                        y=0
X=0                                                        2x + 2(0)= 5000
2(0) + 2y = 5000                                                 2x = 5000
                2y=5000                                                 x=2500
                  Y= 2500                                                               (2500,0)
                                (0,2500)

     4.  Eleminasi kedua persamaan fungsi kendala :
1x + 3y =4000           2
2x + 2y = 5000          1
2x + 6y = 8000
2x + 2y = 5000
                         4y = 3000
                           Y = 750

                         Substitusi ke pers (1)
                         1 *750 + 3y =4000
                                750 + 3y = 4000
                                           3y = 4000-750
                                                3y= 3250
                                                Y= 1083
5.       Subsitusi ke titik koordinat ke dalam
persamaan fungsi tujuan = z = 4000x + 5000y
titik A (0,0) z = 4000 (0) + 5000 (0)
                                = 0
Titik B (4000,0)z = 4000 (4000)+ 5000 (0)
                                = 160.000.00
Titik C (0,2500)z = 4000 (0) + 5000 (2500)
                                = 125.000.00

Grafik
               y
      2500 ●(0,2500)
       2000
       1000
         500
         200
         100                                                                                (2500,0)
              1●(0,1)                                                                                                                 x
             0      20  40  60  100  150  200  1000  2000  2500 3000 4000 4500
                                                                                                                              (4000,0)